Lösung zu Potenzen

1) Berechne folgende Potenzterme

a)	(2cd)3 = 23c3d3 = 8c3d3	b)	(ab)2 = a2b2	c)	− (ab)2 = − a2b2
d)	− (−2ad)3 = − (−8a3d3) = 8a3d3	e)	− (2bc)3 = − 8b3c3	f)	− (ac)3 = − a3c3

2) Vereinfache

a) 103/10−2 = 105 = 100000	b) 2,54/2,54 = 2,50 = 1	c) 2,50/3−4 = 34 = 81
d) 50,5/(−0,5)0 = 50,5 = √5 ≈ 2,24	e) 2−3/2−9 = 26 = 64	f) 243/83 = 33 = 27

... coming soon ...